In Cu (Atomic number Z = 29),which of the fol | vedclass

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(B) The electronic configuration of $Cu$ $(Z = 29)$ is $[Ar] 3d^{10} 4s^1$.Total number of electrons = $29$.In a filled orbital,there are $2$ electron

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$14$ electrons have spin in one direction and $15$ electrons in other direction.

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(B) The electronic configuration of $Cu$ $(Z = 29)$ is $[Ar] 3d^{10} 4s^1$.Total number of electrons = $29$.In a filled orbital,there are $2$ electrons with opposite spins ($+1/2$ and $-1/2$).In $Cu$,there are $14$ fully filled orbitals $(1s, 2s, 2p_x, 2p_y, 2p_z, 3s, 3p_x, 3p_y, 3p_z, 3d_{xy}, 3d_{yz}, 3d_{zx}, 3d_{x^2-y^2}, 3d_{z^2})$ containing $28$ electrons.These $28$ electrons consist of $14$ electrons with spin $+1/2$ and $14$ electrons with spin $-1/2$.The remaining $1$ electron is in the $4s$ orbital,which can have either spin $+1/2$ or $-1/2$.If the $4s$ electron has spin $+1/2$,then total electrons with spin $+1/2$ are $14 + 1 = 15$ and spin $-1/2$ are $14$.If the $4s$ electron has spin $-1/2$,then total electrons with spin $-1/2$ are $14 + 1 = 15$ and spin $+1/2$ are $14$.Thus,$15$ electrons have spin in one direction and $14$ electrons in the other direction.Since this matches option $B$ (rearranged),the correct statement is that $14$ electrons have spin in one direction and $15$ electrons in the other.

In $Cu$ (Atomic number $Z = 29$),which of the following statements regarding the electron spin is correct?

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