Easy
Orbital angular momentum of an electron in $3s$ and $3p$ subshells are:
- A$0, \frac{h}{\sqrt{2} \pi}$
- B$\frac{h}{\sqrt{2} \pi}, 0$
- C$0, \frac{\sqrt{2}h}{2 \pi}$
- D$0, \sqrt{2} \frac{h}{2 \pi}$
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Similar Questions
Identify the element from the following having six unpaired electrons in its observed electronic configuration.
The total number of subshells for which $(n + l) = 7$ is .......
Medium
View SolutionThe number of unpaired electrons in nitrogen is
Easy
View SolutionThe electronic configuration of three elements $A$,$B$,and $C$ are given below. Stable form of $A$ may be represented by the formula:
$A : 1s^2, 2s^2, 2p^6$
$B : 1s^2, 2s^2, 2p^6, 3s^2, 3p^3$
$C : 1s^2, 2s^2, 2p^6, 3s^2, 3p^5$
$A : 1s^2, 2s^2, 2p^6$
$B : 1s^2, 2s^2, 2p^6, 3s^2, 3p^3$
$C : 1s^2, 2s^2, 2p^6, 3s^2, 3p^5$
Medium
View SolutionFor electrons having principal quantum number $n = 3$,the number of $(i)$ subshells and $(ii)$ orbitals would be respectively:
Easy
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