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(D) The intensity of light in an interference pattern is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$. For destructive interference, the phase

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there is some intensity of light in the region of destructive interference

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(D) The intensity of light in an interference pattern is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$. For destructive interference, the phase difference $\phi = (2n+1)\pi$, which leads to $I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2$. If the amplitudes are different, then $I_1 
eq I_2$, which implies $\sqrt{I_1} 
eq \sqrt{I_2}$. Therefore, $I_{min} 
eq 0$. This means that in the region of destructive interference, the waves do not cancel each other out completely, and there remains some residual intensity of light.

If two sources emit light waves of different amplitudes, then:

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