If two sources of light emit waves of differe | vedclass

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(A) In the phenomenon of interference, the intensity of light is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$, where $I_1$ and $I_2$ are the i

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there is some intensity of light in the region of destructive interference.

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(A) In the phenomenon of interference, the intensity of light is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$, where $I_1$ and $I_2$ are the intensities of the two waves.Since $I \propto A^2$, where $A$ is the amplitude, the intensities at the points of destructive interference are given by $I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2 = (A_1 - A_2)^2$.If the amplitudes $A_1$ and $A_2$ are different, then $(A_1 - A_2)^2 
eq 0$.Therefore, the intensity at the region of destructive interference is not zero, meaning there is some residual intensity of light.

If two sources of light emit waves of different amplitudes and interfere, then:

Similar Questions

Write down the condition of constructive interference.

The resultant amplitude in interference with two coherent sources depends upon:

$A$ beam with wavelength $\lambda$ falls on a stack of partially reflecting planes with separation $d$. The angle $\theta$ that the beam should make with the planes so that the beams reflected from successive planes may interfere constructively is (where $n = 1, 2, \dots$)

If two light waves reaching at a point produce destructive interference,then the condition of phase difference is:

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