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(C) In an interference pattern, the intensity $I$ is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$. For destructive interference, the phase dif

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there is some intensity of light in the region of destructive interference.

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(C) In an interference pattern, the intensity $I$ is given by $I = I_1 + I_2 + 2\sqrt{I_1 I_2} \cos \phi$. For destructive interference, the phase difference $\phi = (2n+1)\pi$, so $\cos \phi = -1$. The minimum intensity is $I_{min} = (\sqrt{I_1} - \sqrt{I_2})^2$. If the amplitudes are different, then $I_1 
eq I_2$, which implies $\sqrt{I_1} 
eq \sqrt{I_2}$. Therefore, $I_{min} 
eq 0$. This means that in the region of destructive interference, there is some residual intensity of light instead of complete darkness.

If two sources emit light waves of different amplitudes, then in the interference pattern:

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