(B) When two parallel lines are intersected by a transversal,the interior angles on the same side of the transversal are consecutive interior angles (

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(B) When two parallel lines are intersected by a transversal,the interior angles on the same side of the transversal are consecutive interior angles (also known as co-interior angles). According to the properties of parallel lines,these angles are supplementary,meaning their sum is equal to $180^{\circ}$.

Class 9 Mathematics Lines and Angles Mix Examples - Lines and Angles

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If two parallel lines are intersected by a transversal,then interior angles on the same side of the transversal are $\ldots \ldots . . .$

A
Equal
B
Supplementary
C
Complementary
D
Reflex

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Class 9 Questions

Class 9

Mathematics Questions

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Lines and Angles

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Mix Examples - Lines and Angles

$\angle P$ and $\angle Q$ are supplementary angles. If $\angle P = 11 \angle Q$,then find $\angle P$ and $\angle Q$.

Medium

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In the figure,$AB$,$CD$,and $EF$ are three lines concurrent at $O$. Find the value of $y$. (in $^{\circ}$)

Medium

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If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio $2:3,$ then the greater of the two angles is (in $^{\circ}$)

Medium

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Bisectors of angles $B$ and $C$ of a triangle $ABC$ intersect each other at the point $O$. Prove that $\angle BOC = 90^{\circ} + \frac{1}{2} \angle A$.

Difficult

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In $\Delta ABC$,if $\angle A = \angle B + \angle C$,then $\angle A = \ldots$ (in $^{\circ}$)

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If two parallel lines are intersected by a transversal,then interior angles on the same side of the transversal are $\ldots \ldots . . .$

Similar Questions

$\angle P$ and $\angle Q$ are supplementary angles. If $\angle P = 11 \angle Q$,then find $\angle P$ and $\angle Q$.

In the figure,$AB$,$CD$,and $EF$ are three lines concurrent at $O$. Find the value of $y$. (in $^{\circ}$)

If two interior angles on the same side of a transversal intersecting two parallel lines are in the ratio $2:3,$ then the greater of the two angles is (in $^{\circ}$)

Bisectors of angles $B$ and $C$ of a triangle $ABC$ intersect each other at the point $O$. Prove that $\angle BOC = 90^{\circ} + \frac{1}{2} \angle A$.

In $\Delta ABC$,if $\angle A = \angle B + \angle C$,then $\angle A = \ldots$ (in $^{\circ}$)

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