If two liquids A and B form a minimum boiling | vedclass

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(B) Minimum boiling azeotropes are formed by non-ideal solutions that show a large positive deviation from Raoult's law.In these solutions,the $A-B$ m

Vedclass · Accepted Answer

The total vapour pressure of the mixture is greater than that corresponding to an ideal solution.

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(B) Minimum boiling azeotropes are formed by non-ideal solutions that show a large positive deviation from Raoult's law.In these solutions,the $A-B$ molecular interactions are weaker than the $A-A$ and $B-B$ interactions.Due to these weaker interactions,the molecules escape more easily into the vapour phase,resulting in a total vapour pressure that is greater than that predicted by Raoult's law for an ideal solution.Additionally,for such solutions,the enthalpy of mixing $(\Delta H_{mix})$ is positive and there is a slight increase in volume upon mixing.Therefore,the correct statement is that the total vapour pressure of the mixture is greater than that corresponding to an ideal solution.

If two liquids $A$ and $B$ form a minimum boiling azeotrope at some specific composition,then which statement among the following is correct?

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