If two balls of the same metal weighing 5, g | vedclass

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(C) The kinetic energy of the ball is converted into heat energy upon impact.Let $m$ be the mass of the ball,$v$ be the velocity,$c$ be the specific h

Vedclass · Accepted Answer

Equal for both the balls

Vedclass · Answer

(C) The kinetic energy of the ball is converted into heat energy upon impact.Let $m$ be the mass of the ball,$v$ be the velocity,$c$ be the specific heat capacity of the metal,and $\Delta 	heta$ be the rise in temperature.The heat energy produced is $Q = \frac{1}{2}mv^2$.This heat energy is used to raise the temperature: $Q = mc\Delta 	heta$.Equating the two: $\frac{1}{2}mv^2 = mc\Delta 	heta$.Simplifying for $\Delta 	heta$: $\Delta 	heta = \frac{v^2}{2c}$.Since the velocity $v$ and the specific heat capacity $c$ are the same for both balls,the rise in temperature $\Delta 	heta$ is independent of the mass $m$.Therefore,the temperature rise is equal for both balls.

List-$I$	List-$II$
$A$. When ice melts into water	$I$. Volume increases
$B$. When water changes into steam	$II$. Volume decreases
$C$. Melting point of ice	$III$. Increases with increase of pressure
$D$. Boiling point of water	$IV$. Decreases with increase in pressure

If two balls of the same metal weighing $5\, g$ and $10\, g$ strike a target with the same velocity,and the heat energy developed is used solely for raising their temperature,then the temperature rise will be higher:

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