If the volume of a sphere increases at the rate of $2 \pi \text{ cm}^3/\text{s}$,then the rate of increase of its radius (in $\text{cm/s}$),when the volume is $288 \pi \text{ cm}^3$,is

  • A
    $\frac{1}{36}$
  • B
    $\frac{1}{72}$
  • C
    $\frac{1}{18}$
  • D
    $\frac{1}{9}$

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