If the vertices of a triangle are (0,0),(6,0) | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) Let the vertices be $A(0,0)$,$B(6,0)$,and $C(6,8)$.The lengths of the sides are:$c = AB = \sqrt{(6-0)^2 + (0-0)^2} = 6$$a = BC = \sqrt{(6-6)^2 + (

Vedclass · Accepted Answer

$(4,2)$

Vedclass · Answer

(C) Let the vertices be $A(0,0)$,$B(6,0)$,and $C(6,8)$.The lengths of the sides are:$c = AB = \sqrt{(6-0)^2 + (0-0)^2} = 6$$a = BC = \sqrt{(6-6)^2 + (8-0)^2} = 8$$b = AC = \sqrt{(6-0)^2 + (8-0)^2} = \sqrt{36+64} = 10$The coordinates of the incentre $(I)$ are given by $\left( \frac{ax_1 + bx_2 + cx_3}{a+b+c}, \frac{ay_1 + by_2 + cy_3}{a+b+c} \right)$.Substituting the values:$I = \left( \frac{8(0) + 10(6) + 6(6)}{8+10+6}, \frac{8(0) + 10(0) + 6(8)}{8+10+6} \right)$$I = \left( \frac{0 + 60 + 36}{24}, \frac{0 + 0 + 48}{24} \right)$$I = \left( \frac{96}{24}, \frac{48}{24} \right) = (4, 2)$.

If the vertices of a triangle are $(0,0)$,$(6,0)$,and $(6,8)$,then its incentre will be:

Similar Questions

If $A(4, -3)$,$B(3, -2)$,and $C(2, 8)$ are the vertices of a triangle,what is the distance of its centroid from the $y$-axis?

The vertices of a triangle are $A(4, -2)$,$B(2, 3)$,and $C(5, -4)$. Find the equation of the median drawn from $C$.

In $\triangle ABC$,if $A=(1,2)$ and the equations of the medians through $B$ and $C$ are $x+y=5$ and $x=4$ respectively,then the area of $\triangle ABC$ is

Let $O(0,0), P(3,4), Q(6,0)$ be the vertices of the triangle $OPQ$. The point $R$ inside the triangle $OPQ$ is such that the triangles $OPR, PQR, OQR$ are of equal area. The coordinates of $R$ are

The circumcentre of the triangle formed by the points $A(1, \sqrt{3})$,$B(-1, -\sqrt{3})$,and $C(3, -\sqrt{3})$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module