If the vertices of a triangle are (a, b - c), | vedclass

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(B) The centroid $(G)$ of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by $G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac

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On $x$-axis

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(B) The centroid $(G)$ of a triangle with vertices $(x_1, y_1)$,$(x_2, y_2)$,and $(x_3, y_3)$ is given by $G = \left( \frac{x_1 + x_2 + x_3}{3}, \frac{y_1 + y_2 + y_3}{3} \right)$.Given vertices are $(a, b - c)$,$(b, c - a)$,and $(c, a - b)$.The $x$-coordinate of the centroid is $x = \frac{a + b + c}{3}$.The $y$-coordinate of the centroid is $y = \frac{(b - c) + (c - a) + (a - b)}{3} = \frac{0}{3} = 0$.Since the $y$-coordinate is $0$,the centroid lies on the $x$-axis.

If the vertices of a triangle are $(a, b - c)$,$(b, c - a)$,and $(c, a - b)$,then the centroid of the triangle lies

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