If the vertices of Delta ABC are A(9,5), B(6, | vedclass

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(D) Since $\overline{BE}$ is the median of $\Delta ABC$ to the side $\overline{AC}$,$E$ is the midpoint of $\overline{AC}$.The coordinates of $A$ are

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$3$

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(D) Since $\overline{BE}$ is the median of $\Delta ABC$ to the side $\overline{AC}$,$E$ is the midpoint of $\overline{AC}$.The coordinates of $A$ are $(9,5)$ and $C$ are $(3,3)$.Using the midpoint formula,the coordinates of $E = \left(\frac{9+3}{2}, \frac{5+3}{2}\right) = \left(\frac{12}{2}, \frac{8}{2}\right) = (6,4)$.The length of median $\overline{BE}$ is the distance between $B(6,7)$ and $E(6,4)$.Using the distance formula,$BE = \sqrt{(6-6)^2 + (7-4)^2} = \sqrt{0^2 + 3^2} = \sqrt{9} = 3$.

If the vertices of $\Delta ABC$ are $A(9,5), B(6,7)$ and $C(3,3)$,then the length of median $\overline{BE}$ is.......

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