If the velocity of a particle is $v = At + Bt^2$,where $A$ and $B$ are constants,then the distance travelled by it between $1 \ s$ and $2 \ s$ is

  • A
    $3A + 7B$
  • B
    $\frac{3}{2}A + \frac{7}{3}B$
  • C
    $\frac{A}{2} + \frac{B}{3}$
  • D
    $\frac{3}{2}A + 4B$

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