If the vectors $2 \hat{i}-3 \hat{j}+6 \hat{k}$ and $\vec{b}$ are collinear and $|\vec{b}|=14$,then $\vec{b}$ has the value

  • A
    $4 \hat{i}+6 \hat{j}+12 \hat{k}$
  • B
    $-4 \hat{i}-6 \hat{j}-12 \hat{k}$
  • C
    $4 \hat{i}-6 \hat{j}+12 \hat{k}$
  • D
    $12 \hat{i}+5 \hat{j}+\sqrt{17} \hat{k}$

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