If the sum of one-half and one-fifth of a num | vedclass

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(C) Let the number be $x$.According to the problem,the sum of one-half and one-fifth of the number exceeds one-third of the number by $7 \frac{1}{3} =

Vedclass · Accepted Answer

$20$

Vedclass · Answer

(C) Let the number be $x$.According to the problem,the sum of one-half and one-fifth of the number exceeds one-third of the number by $7 \frac{1}{3} = \frac{22}{3}$.So,the equation is: $\frac{x}{2} + \frac{x}{5} = \frac{x}{3} + \frac{22}{3}$.Rearranging the terms to solve for $x$: $\frac{x}{2} + \frac{x}{5} - \frac{x}{3} = \frac{22}{3}$.The least common multiple of $2, 5,$ and $3$ is $30$.$\frac{15x + 6x - 10x}{30} = \frac{22}{3}$.$\frac{11x}{30} = \frac{22}{3}$.$x = \frac{22}{3} 	imes \frac{30}{11} = 2 	imes 10 = 20$.Therefore,the number is $20$.

If the sum of one-half and one-fifth of a number exceeds one-third of that number by $7 \frac{1}{3},$ the number is

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