If the students of 9^{th} class are arranged | vedclass

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(D) To find the number of students that can be arranged in rows of $6, 8, 12$,or $16$ without any student being left behind,we need to find the Least

Vedclass · Accepted Answer

$96$

Vedclass · Answer

(D) To find the number of students that can be arranged in rows of $6, 8, 12$,or $16$ without any student being left behind,we need to find the Least Common Multiple $(L.C.M.)$ of these numbers.$L.C.M.$ of $6, 8, 12, 16$:$2$$6, 8, 12, 16$$2$$3, 4, 6, 8$$2$$3, 2, 3, 4$$2$$3, 1, 3, 2$$3$$3, 1, 3, 1$$1, 1, 1, 1$$L.C.M. = 2 	imes 2 	imes 2 	imes 2 	imes 3 = 48$.The number of students must be a multiple of $48$. Among the given options,$96$ is a multiple of $48$ $(48 	imes 2 = 96)$.

If the students of $9^{th}$ class are arranged in rows of $6, 8, 12$ or $16$,no student is left behind. The possible number of students in the class is

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