If the straight line $4x + 3y + \lambda = 0$ touches the circle $2({x^2} + {y^2}) = 5$, then $\lambda $ is
If the straight line $4x + 3y + \lambda = 0$ touches the circle $2({x^2} + {y^2}) = 5$, then $\lambda $ is
- A
$\frac{{5\sqrt 5 }}{2}$
- B
$5\sqrt 2 $
- C
$\frac{{5\sqrt 5 }}{4}$
- D
$\frac{{5\sqrt {10} }}{2}$
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