If the solution for the differential equation $y^2 dx + (x^2 - xy - y^2) dy = 0$ at $(2, 1)$ is $x + y = k(xy^2 - y^3)$,then $k =$

  • A
    $-3$
  • B
    $-4$
  • C
    $4$
  • D
    $3$

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The general solution of the differential equation $\left(\frac{y}{x}\right) \cos \left(\frac{y}{x}\right) dx - \left[\left(\frac{x}{y}\right) \sin \left(\frac{y}{x}\right) + \cos \left(\frac{y}{x}\right)\right] dy = 0$ is:

If $\frac{dy}{dx} = f(x, y)$ is a homogeneous differential equation,then the general form of $f(x, y)$ is

$I: y^{\prime}=\frac{y+x}{x} ; \quad II: y^{\prime}=\frac{x^2+y}{x^3} ; \quad III: y^{\prime}=\frac{2xy}{y^2-x^2}$
$S1$: Differential equations given by $I$ and $II$ are homogeneous differential equations.
$S2$: Differential equations given by $II$ and $III$ are homogeneous differential equations.
$S3$: Differential equations given by $I$ and $III$ are homogeneous differential equations.

Let $f(x) = \sqrt{\lim_{r \rightarrow x} \left\{ \frac{2r^2 \left[(f(r))^2 - f(x)f(r)\right]}{r^2 - x^2} - r^3 e^{\frac{f(r)}{r}} \right\}}$ be differentiable in $(-\infty, 0) \cup (0, \infty)$ and $f(1) = 1$. Then the value of $ea$,such that $f(a) = 0$,is equal to:

For two events $A$ and $B$,$P(B) \neq 0$ and $P(A \mid B) = 1$,then which of the following is true?

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