If the resistivity of a $0.8 \ M \ KCl$ solution is $2.5 \times 10^{-3} \ \Omega \ cm$,calculate the molar conductivity of the solution.

• A
  $3 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$
• B
  $2 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$
• C
  $4 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$
• D
  $5 \times 10^{5} \ \Omega^{-1} \ cm^{2} \ mol^{-1}$