What is the conductivity of $0.02 \ M$ $AgNO_3$ solution having cell constant $1.1 \ cm^{-1}$ and resistance $94.5 \ \Omega$?
- A$0.0216 \ \Omega^{-1} \ cm^{-1}$
- B$0.0116 \ \Omega^{-1} \ cm^{-1}$
- C$0.0416 \ \Omega^{-1} \ cm^{-1}$
- D$0.0859 \ \Omega^{-1} \ cm^{-1}$
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The resistance of a $0.01\, M$ solution of an $Hg_2Cl_2$ electrolyte was found to be $210\, \Omega$ at $298\, K$ using a conductivity cell with a cell constant of $0.63\, m^{-1}$. The equivalent conductance of the solution is:
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View SolutionThe resistivity of a $0.8 \ M$ solution of an electrolyte is $5 \times 10^{-3} \ \Omega \ cm$. Its molar conductivity is $..... \times 10^4 \ \Omega^{-1} \ cm^2 \ mol^{-1}$. (Nearest integer)
What is the conductivity of $0.05 \ M$ $KCl$ solution if cell constant is $1.32 \ cm^{-1}$ and resistance is $528 \ \Omega$?
$A$ conductivity cell is filled with $0.01 \ M \ KCl$ and gives a resistance of $484 \ \Omega$. The conductivity of the solution is $0.00141 \ \Omega^{-1} \ cm^{-1}$ at $25^{\circ}C$. What is the cell constant (in $cm^{-1}$)?
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