If the ratio of the roots of ax^2 + 2bx + c = | vedclass

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(B) Let the roots of the equation $ax^2 + 2bx + c = 0$ be $\alpha$ and $\beta$ such that $\frac{\alpha}{\beta} = \frac{m}{n}$.From the properties of q

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$\frac{b^2}{ac} = \frac{q^2}{pr}$

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(B) Let the roots of the equation $ax^2 + 2bx + c = 0$ be $\alpha$ and $\beta$ such that $\frac{\alpha}{\beta} = \frac{m}{n}$.From the properties of quadratic equations,the sum of roots is $\alpha + \beta = -\frac{2b}{a}$ and the product of roots is $\alpha\beta = \frac{c}{a}$.Using the relation $\frac{(\alpha + \beta)^2}{\alpha\beta} = \frac{(\frac{m}{n} + 1)^2}{\frac{m}{n}} = \frac{(m+n)^2}{mn}$,we get $\frac{(-2b/a)^2}{c/a} = \frac{4b^2/a^2}{c/a} = \frac{4b^2}{ac} = \frac{(m+n)^2}{mn}$.Thus,$\frac{b^2}{ac} = \frac{(m+n)^2}{4mn}$.Similarly,for the equation $px^2 + 2qx + r = 0$,if the ratio of roots is $\frac{m}{n}$,then $\frac{q^2}{pr} = \frac{(m+n)^2}{4mn}$.Equating the two expressions,we get $\frac{b^2}{ac} = \frac{q^2}{pr}$.

If the ratio of the roots of $ax^2 + 2bx + c = 0$ is the same as the ratio of the roots of $px^2 + 2qx + r = 0$,then

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