If the range of a gun which fires a shell with muzzle speed $V$ is $R$,then the angle of elevation of the gun is

  • A
    $\cos^{-1}\left(\frac{V^2}{Rg}\right)$
  • B
    $\cos^{-1}\left(\frac{gR}{V^2}\right)$
  • C
    $\frac{1}{2}\left(\frac{V^2}{Rg}\right)$
  • D
    $\frac{1}{2}\sin^{-1}\left(\frac{gR}{V^2}\right)$

Explore More

Similar Questions

$A$ particle having kinetic energy $K$ is projected at $60^{\circ}$ with the horizontal. The kinetic energy at the highest point is

$A$ particle is projected from the ground with an initial speed of $v$ at an angle of projection $\theta$. The average velocity of the particle between its time of projection and the time it reaches the highest point of its trajectory is

The trajectory of a projectile is

$A$ boy throws a ball with a velocity $u$ at an angle $\theta$ with the horizontal. At the same instant,he starts running with a uniform velocity to catch the ball before it hits the ground. To achieve this,he should run with a velocity of

$A$ particle is projected upwards with a velocity of $100 \ m/s$ at an angle of $60^{\circ}$ with the vertical. Find the time when the particle will move perpendicular to its initial direction,$.....$ seconds (take $g = 10 \ m/s^2$):-

Difficult
View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo