If the radius of a coil is halved and the number of turns doubled, then the magnetic field at the centre of the coil, for the same current will
get doubled
get halved
become $4$ times
remain unchanged
According to Biot-Savart law magnetic field ...... at point of axis of wire.
A current carrying loop consists of $3$ identical quarter circles of radius $\mathrm{R}$, lying in the positive quadrants of the $\mathrm{xy}$ , $\mathrm{yz}$ and $\mathrm{zx}$ planes with their centres at the origin, joined together. Find the direction and magnitude of $\mathrm{B}$ at the origin.
Find the magnetic field at the point $P$ in figure. The curved portion is a semicircle connected to two long straight wires.
The magnetic induction at the centre of a current carrying circular coil of radius $10\, cm$ is $5\sqrt 5 \,times$ the magnetic induction at a point on its axis. The distance of the point from the centre of the coil (in $cm$) is
A closely wound flat circular coil of $25$ $turns$ of wire has diameter of $10\, cm$ and carries a current of $4\, ampere$. Determine the flux density at the centre of a coil