If the product of the zeros of p(x) = ax^{2} | vedclass

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(C) For a quadratic polynomial $p(x) = ax^{2} + bx + c$,the product of the zeros is given by the formula $\frac{c}{a}$.Given the polynomial $p(x) = ax

Vedclass · Accepted Answer

$-3/2$

Vedclass · Answer

(C) For a quadratic polynomial $p(x) = ax^{2} + bx + c$,the product of the zeros is given by the formula $\frac{c}{a}$.Given the polynomial $p(x) = ax^{2} - 6x - 6$,we identify the coefficients as $A = a$,$B = -6$,and $C = -6$.The product of the zeros is given as $4$.Therefore,$\frac{C}{A} = 4$.Substituting the values,we get $\frac{-6}{a} = 4$.Solving for $a$: $4a = -6$,which implies $a = -\frac{6}{4} = -\frac{3}{2}$.Thus,the correct value of $a$ is $-\frac{3}{2}$.

If the product of the zeros of $p(x) = ax^{2} - 6x - 6$ is $4$,then $a = $ ............

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