Obtain the value of the following polynomial at the given values of $x$: $p(x) = 10 - 5x + 3x^2 - x^3$; at $x = 2$ and $x = -2$.

For the cubic polynomial $p(x) = ax^{3} + bx^{2} + cx + d$; if $a = 3$,$b = -5$,$c = -11$,and $d = -3$,then the cubic polynomial is:

If $\alpha, \beta$ and $\gamma$ are the zeros of the cubic polynomial $p(x) = x^{3} + x^{2} - 17x + 15$,then $\alpha\beta + \beta\gamma + \gamma\alpha = \dots$

Prove that $-6, -\frac{1}{2}$ and $1$ are the zeros of the cubic polynomial $p(x) = 2x^3 + 11x^2 - 7x - 6$. Also,verify the relationship between the zeros and the coefficients.

Divide $x^{4}+4 x^{3}-2 x^{2}-12 x+9$ by $x^{2}-2 x+1$.

The zeros of the cubic polynomial $p(x) = ax^3 + bx^2 + cx + d$; where $a \neq 0$ and $a, b, c, d \in R$,are $\alpha, \beta$,and $\gamma$. Then $\alpha + \beta + \gamma = \ldots$