If the product of the lengths of the perpendiculars drawn from the foci to the tangent $y = \frac{-3}{4}x + 3\sqrt{2}$ of the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ is $9$,then the eccentricity of that ellipse is

  • A
    $\frac{\sqrt{2}}{3}$
  • B
    $\frac{\sqrt{5}}{6}$
  • C
    $\frac{1}{9}$
  • D
    $\frac{\sqrt{7}}{4}$

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