If the permutations of A, B, C, D, E taken al | vedclass

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(D) To find the rank of the word $DEBAC$,we list the letters in alphabetical order: $A, B, C, D, E$.$1$. Words starting with $A$: $4! = 24$ words.$2$.

Vedclass · Accepted Answer

$93$

Vedclass · Answer

(D) To find the rank of the word $DEBAC$,we list the letters in alphabetical order: $A, B, C, D, E$.$1$. Words starting with $A$: $4! = 24$ words.$2$. Words starting with $B$: $4! = 24$ words.$3$. Words starting with $C$: $4! = 24$ words.$4$. Words starting with $D$:- $DA...$: $3! = 6$ words.- $DB...$: $3! = 6$ words.- $DC...$: $3! = 6$ words.- $DE...$:- $DEABC$: $1$ word.- $DEACB$: $1$ word.- $DEBAC$: $1$ word.Total rank = $24 + 24 + 24 + 6 + 6 + 6 + 1 + 1 + 1 = 93$.

If the permutations of $A, B, C, D, E$ taken all together are written down in alphabetical order as in a dictionary and numbered,then the rank of the permutation $DEBAC$ is

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