If the maximum and minimum voltage of an ampl | vedclass

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(D) The maximum voltage of an amplitude modulated wave is given by $V_{max} = A_c + A_m$,where $A_c$ is the carrier amplitude and $A_m$ is the message

Vedclass · Accepted Answer

$m = \frac{V_{max} - V_{min}}{V_{max} + V_{min}}$

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(D) The maximum voltage of an amplitude modulated wave is given by $V_{max} = A_c + A_m$,where $A_c$ is the carrier amplitude and $A_m$ is the message signal amplitude.The minimum voltage is given by $V_{min} = A_c - A_m$.Adding these two equations: $V_{max} + V_{min} = 2A_c$,so $A_c = \frac{V_{max} + V_{min}}{2}$.Subtracting these two equations: $V_{max} - V_{min} = 2A_m$,so $A_m = \frac{V_{max} - V_{min}}{2}$.The modulation factor $m$ is defined as the ratio of the message signal amplitude to the carrier signal amplitude: $m = \frac{A_m}{A_c}$.Substituting the values: $m = \frac{(V_{max} - V_{min})/2}{(V_{max} + V_{min})/2} = \frac{V_{max} - V_{min}}{V_{max} + V_{min}}$.

If the maximum and minimum voltage of an amplitude modulated wave are $V_{max}$ and $V_{min}$ respectively,then the modulation factor is:

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