If the line 2x + y + k = 0 is normal to the p | vedclass

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(C) The equation of the parabola is $y^2 = -8x$. Comparing this with $y^2 = -4ax$,we get $a = 2$.The equation of the line is $y = -2x - k$,which is in

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$ -24 $

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(C) The equation of the parabola is $y^2 = -8x$. Comparing this with $y^2 = -4ax$,we get $a = 2$.The equation of the line is $y = -2x - k$,which is in the form $y = mx + c$,where $m = -2$ and $c = -k$.The condition for the line $y = mx + c$ to be a normal to the parabola $y^2 = -4ax$ is $c = -2am - am^3$.Substituting the values $a = 2$,$m = -2$,and $c = -k$ into the condition:$-k = -2(2)(-2) - 2(-2)^3$$-k = 8 - 2(-8)$$-k = 8 + 16$$-k = 24$$k = -24$.

If the line $2x + y + k = 0$ is normal to the parabola $y^2 = -8x$,then the value of $k$ will be

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