If the line $3x + 4y - 1 = 0$ touches the circle ${(x - 1)^2} + {(y - 2)^2} = {r^2}$, then the value of $r$ will be
If the line $3x + 4y - 1 = 0$ touches the circle ${(x - 1)^2} + {(y - 2)^2} = {r^2}$, then the value of $r$ will be
- A
$2$
- B
$5$
- C
$\frac{{12}}{5}$
- D
$\frac{2}{5}$
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- [JEE MAIN 2019]
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