If the length of a clock pendulum increases by $0.2 \%$ due to atmospheric temperature rise,then the loss in time of the clock per day is ........... $s$.

The length of a simple pendulum is increased by $44\%$. The percentage increase in its time period will be ..... $\%$

The acceleration due to gravity on the surface of the moon is $1.7 \; m s^{-2}$. What is the time period of a simple pendulum on the surface of the moon if its time period (in $s$) on the surface of the earth is $3.5 \; s$? ($g$ on the surface of the earth is $9.8 \; m s^{-2}$)

The length of a seconds pendulum on the surface of the Earth is $1\, m$. The length of a seconds pendulum on the surface of the Moon,where $g$ is $1/6$th the value of $g$ on the surface of the Earth,is:

$A$ chimpanzee swinging on a swing in a sitting position,stands up suddenly,the time period will

On a planet,a freely falling body takes $2 \, s$ when it is dropped from a height of $8 \, m$. The time period of a simple pendulum of length $1 \, m$ on that planet is ..... $s$.