If the foot of the perpendicular from $(0,0,0)$ to a plane is $(1,2,3)$,then the equation of the plane is

  • A
    $x+2y+3z=14$
  • B
    $x+2y+3z=10$
  • C
    $x+2y+3z+14=0$
  • D
    $x+2y-3z=14$

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Consider three planes:
$P_1: x-y+z=1$
$P_2: x+y-z=-1$
$P_3: x-3y+3z=2$
Let $L_1, L_2, L_3$ be the lines of intersection of the planes $P_2$ and $P_3$,$P_3$ and $P_1$,and $P_1$ and $P_2$,respectively.
$STATEMENT-1$: At least two of the lines $L_1, L_2$ and $L_3$ are non-parallel.
$STATEMENT-2$: The three planes do not have a common point.

The equation of the plane in normal form passing through the point $A(\vec{a})$,parallel to a vector $\vec{b}$ and containing a vector $\vec{c}$ is

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