If the focus of the parabola is (3, -4) and t | vedclass

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(A) By the definition of a parabola,the distance from any point $P(x, y)$ on the parabola to the focus $S(3, -4)$ is equal to the perpendicular distan

Vedclass · Accepted Answer

$(x - 3)^2 = -16y$

Vedclass · Answer

(A) By the definition of a parabola,the distance from any point $P(x, y)$ on the parabola to the focus $S(3, -4)$ is equal to the perpendicular distance from $P$ to the directrix $y - 4 = 0$.$SP = PM$$\sqrt{(x - 3)^2 + (y + 4)^2} = |y - 4|$Squaring both sides:$(x - 3)^2 + (y + 4)^2 = (y - 4)^2$$(x - 3)^2 + y^2 + 8y + 16 = y^2 - 8y + 16$$(x - 3)^2 = -8y - 8y$$(x - 3)^2 = -16y$

If the focus of the parabola is $(3, -4)$ and the directrix is $y - 4 = 0,$ then the equation of the parabola is :-

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