If the extremities of the latus rectum having positive ordinate of the ellipse $\frac{x^2}{a^2} + \frac{y^2}{b^2} = 1$ $(a > b)$ lie on the parabola $x^2 + 2ay - 4 = 0$,then the points $(a, b)$ lie on the curve:

  • A
    $xy = 4$
  • B
    $x^2 + y^2 = 4$
  • C
    $\frac{x^2}{4} + \frac{y^2}{1} = 1$
  • D
    $\frac{x^2}{4} - \frac{y^2}{1} = 1$

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