If the equation of the hyperbola having $(8,3)$ and $(0,3)$ as foci and $\frac{4}{3}$ as eccentricity is $\frac{(x-\alpha)^2}{p}-\frac{(y-\beta)^2}{q}=1$,then $p+q=$

  • A
    $\beta^2$
  • B
    $\alpha+\beta$
  • C
    $\alpha^2$
  • D
    $\alpha \beta$

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