If the distance between the points (4, p) and | vedclass

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(B) According to the distance formula,the distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 -

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$\pm 4$

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(B) According to the distance formula,the distance $d$ between two points $(x_1, y_1)$ and $(x_2, y_2)$ is given by $d = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$.Given points are $(4, p)$ and $(1, 0)$ with distance $d = 5$.Substituting the values into the formula:$5 = \sqrt{(1 - 4)^2 + (0 - p)^2}$$5 = \sqrt{(-3)^2 + (-p)^2}$$5 = \sqrt{9 + p^2}$Squaring both sides:$25 = 9 + p^2$$p^2 = 25 - 9$$p^2 = 16$$p = \pm \sqrt{16}$$p = \pm 4$Thus,the value of $p$ is $\pm 4$.

If the distance between the points $(4, p)$ and $(1, 0)$ is $5,$ then the value of $p$ is

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