If the distance between the plates of a parallel plate capacitor of capacity $10 \mu F$ is doubled,then the new capacity will be: (in $\mu F$)

In a parallel plate capacitor,the capacity increases if

$A$ parallel plate capacitor has rectangular plates of area $400 \, cm^2$ separated by a distance of $2 \, mm$ with air as the medium. If a potential difference of $200 \, V$ is applied across the capacitor,what is the charge on the plates?

Two identical thin metal plates have charges $q_{1}$ and $q_{2}$ respectively,such that $q_{1} > q_{2}$. The plates are brought close to each other to form a parallel plate capacitor of capacitance $C$. The potential difference between them is:

The area of each plate of a parallel plate capacitor is $100 \, cm^2$ and the distance between the plates is $1 \, mm$. It is filled with mica of dielectric constant $6$. The radius of the equivalent capacity of the sphere will be.......$m$.

The intensity of the electric field at a point between the plates of a charged parallel plate capacitor: