If the distance between the plates of a capacitor having capacity $C$ and charge $Q$ is doubled,then the work done will be:

Consider a parallel plate capacitor of area $A$ (of each plate) and separation $d$ between the plates. If $E$ is the electric field and $\varepsilon_0$ is the permittivity of free space between the plates,then the potential energy stored in the capacitor is $:-$

The energy stored in a capacitor of capacitance $C$ charged to a potential $V$ is:

In a defibrillator,a $40\ \mu F$ capacitor is charged to $3000\ V$. If the stored energy of the capacitor is discharged through the patient during a pulse of duration $2\ ms$,what is the power delivered to the patient in $kW$?

How much work is required to increase the voltage of a $6\,\mu F$ capacitor from $10\ V$ to $20\ V$?

$A$ battery is used to charge a parallel plate capacitor until the potential difference between the plates becomes equal to the e.m.f. of the battery. The ratio of the energy stored in the capacitor to the work done by the battery will be