If the distance between the plates of a capacitor having capacity $C$ and charge $Q$ is doubled then work done will be
If the distance between the plates of a capacitor having capacity $C$ and charge $Q$ is doubled then work done will be
- A
$\frac{{{Q^2}}}{{4C}}$
- B
$\frac{{{Q^2}}}{{2C}}$
- C
$\frac{{{Q^2}}}{{C}}$
- D
$\frac{{{2Q^2}}}{{C}}$
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