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(A) The relationship between the dielectric constant $K$ and the electric susceptibility $\chi_{e}$ is given by the formula:$K = 1 + \frac{\chi_{e}}{\

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$\frac{\varepsilon_0}{3}$

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(A) The relationship between the dielectric constant $K$ and the electric susceptibility $\chi_{e}$ is given by the formula:$K = 1 + \frac{\chi_{e}}{\varepsilon_0}$Given that $K = \frac{4}{3}$,we substitute this value into the equation:$\frac{4}{3} = 1 + \frac{\chi_{e}}{\varepsilon_0}$Subtracting $1$ from both sides:$\frac{\chi_{e}}{\varepsilon_0} = \frac{4}{3} - 1$$\frac{\chi_{e}}{\varepsilon_0} = \frac{1}{3}$Therefore,the electric susceptibility is:$\chi_{e} = \frac{\varepsilon_0}{3}$

If the dielectric constant of a substance is $K = \frac{4}{3}$,then the electric susceptibility $\chi_{e}$ is

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