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(C) The resistance $R$ of a conducting wire is given by the formula $R = \rho \frac{L}{A}$,where $\rho$ is the resistivity,$L$ is the length,and $A$ i

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(C) The resistance $R$ of a conducting wire is given by the formula $R = \rho \frac{L}{A}$,where $\rho$ is the resistivity,$L$ is the length,and $A$ is the cross-sectional area of the wire.From this relation,it is clear that resistance is inversely proportional to the cross-sectional area $(R \propto \frac{1}{A})$.If the area $A$ is doubled $(A' = 2A)$,the new resistance $R'$ becomes $R' = \rho \frac{L}{2A} = \frac{1}{2} R$.Therefore,the resistance becomes half of its original value.

If the cross-sectional area of a conducting wire is doubled,what will be the effect on its resistance?

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