If the conductance and specific conductance of a solution are both $1$,then its cell constant would be:

If the conductivity of a $0.5 \ M \ KCl$ solution at $298 \ K$ is $0.024 \ S \ cm^{-1}$,then the molar conductivity of the solution would be $S \ cm^2 \ mol^{-1}$.

The conductivity of a strong electrolyte is:

Which of the following decreases on dilution of an electrolytic solution?

Conductivity of a saturated solution of a sparingly soluble salt $AB$ at $298 \ K$ is $1.85 \times 10^{-5} \ S \ m^{-1}$. Solubility product of the salt $AB$ at $298 \ K$ is. Given $\Lambda_{m}^{\circ}(AB) = 140 \times 10^{-4} \ S \ m^{2} \ mol^{-1}$.

The resistance of a $1 \, N$ solution of a salt is $50 \, \Omega$. The two platinum electrodes in the solution are $2.1 \, cm$ apart and each has an area of $4.2 \, cm^2$. Calculate the equivalent conductivity of the solution.