The resistance of a $1 \, N$ solution of a salt is $50 \, \Omega$. The two platinum electrodes in the solution are $2.1 \, cm$ apart and each has an area of $4.2 \, cm^2$. Calculate the equivalent conductivity of the solution.

Cell constant of a conductivity cell is $0.9 \ cm^{-1}$ and resistance shown by $AgNO_3$ solution is $6530 \ \Omega$. What is the conductivity of $AgNO_3$ solution?

The conductivity of $0.005 \ M$ $NaI$ solution at $25^{\circ} C$ is $6.07 \times 10^{-4} \ \Omega^{-1} \ cm^{-1}$. Calculate its molar conductivity.

Calculate molar conductivity at infinite dilution for $NaBr$ if molar conductivity at infinite dilution for $NaCl$,$KBr$ and $KCl$ are $126$,$152$ and $150 \ \Omega^{-1} \ cm^2 \ mol^{-1}$ respectively.

Resistance of a conductivity cell filled with $0.1 \, mol \, L^{-1}$ $KCl$ solution is $100 \, \Omega$. If the resistance of the same cell when filled with $0.02 \, mol \, L^{-1}$ $KCl$ solution is $520 \, \Omega$,calculate the conductivity and molar conductivity of $0.02 \, mol \, L^{-1} \, KCl$ solution. The conductivity of $0.1 \, mol \, L^{-1} \, KCl$ solution is $1.29 \, S / m$.

The ionic conductances of $Ba^{2+}$ and $Cl^{-}$ at infinite dilution are $127$ and $76 \ \Omega^{-1} \ cm^2 \ eq^{-1}$ respectively. The equivalent conductance of $BaCl_2$ at infinite dilution is ..... (in $.5$)