If the centre of a circle is $(2, 3)$ and a tangent is $x + y = 1$, then the equation of this circle is
If the centre of a circle is $(2, 3)$ and a tangent is $x + y = 1$, then the equation of this circle is
- A
${(x - 2)^2} + {(y - 3)^2} = 8$
- B
${(x - 2)^2} + {(y - 3)^2} = 3$
- C
${(x + 2)^2} + {(y + 3)^2} = 2\sqrt 2 $
- D
${(x - 2)^2} + {(y - 3)^2} = 2\sqrt 2 $
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