If the angles of dip at two places are 30^o a | vedclass

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Question

(a)The horizontal components are ${({B_H})_1} = B\cos {\phi _1}$and ${({B_H})_2} = B\cos {\phi _2}$
$	herefore \,\frac{{{{({B_H})}_1}}}{{{{({B_{^H}}

Vedclass · Accepted Answer

$\sqrt 3 :\sqrt 2 $

Vedclass · Answer

(a)The horizontal components are ${({B_H})_1} = B\cos {\phi _1}$and ${({B_H})_2} = B\cos {\phi _2}$
$	herefore \,\frac{{{{({B_H})}_1}}}{{{{({B_{^H}})}_2}}} = \frac{{\cos {\phi _1}}}{{\cos {\phi _2}}} = \frac{{\cos {{30}^o}}}{{\cos {{45}^o}}} = \frac{{\sqrt 3 }}{2} 	imes \sqrt 2 = \frac{{\sqrt 3 }}{{\sqrt 2 }}$

If the angles of dip at two places are $30^o$ and $45^o$ respectively, then the ratio of horizontal components of earth's magnetic field at the two places will be

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