If the angle between the circles $x^2+y^2-2x-4y+c=0$ and $x^2+y^2-4x-2y+4=0$ is $60^{\circ}$,then $c$ is equal to

  • A
    $\frac{3 \pm \sqrt{5}}{2}$
  • B
    $\frac{6 \pm \sqrt{5}}{2}$
  • C
    $\frac{9 \pm \sqrt{5}}{2}$
  • D
    $\frac{7 \pm \sqrt{5}}{2}$

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