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Question

(A) The intensity $I$ of an electromagnetic wave in terms of the magnetic field amplitude $B_0$ is given by the formula: $I = \frac{B_0^2 c}{2 \mu_0}$

Vedclass · Accepted Answer

$5.8 	imes 10^6 \ W/m^2$

Vedclass · Answer

(A) The intensity $I$ of an electromagnetic wave in terms of the magnetic field amplitude $B_0$ is given by the formula: $I = \frac{B_0^2 c}{2 \mu_0}$.Given: $B_0 = 2.2 	imes 10^{-4} \ T$,$c = 3 	imes 10^8 \ m/s$,and $\mu_0 = 4 \pi 	imes 10^{-7} \ T \cdot m/A$.Substituting the values:$I = \frac{(2.2 	imes 10^{-4})^2 	imes 3 	imes 10^8}{2 	imes 4 \pi 	imes 10^{-7}}$$I = \frac{4.84 	imes 10^{-8} 	imes 3 	imes 10^8}{8 \pi 	imes 10^{-7}}$$I = \frac{14.52}{25.13 	imes 10^{-7}} \approx 5.77 	imes 10^6 \ W/m^2$.Rounding to the nearest value,we get $I \approx 5.8 	imes 10^6 \ W/m^2$.

If the amplitude of the magnetic field in a travelling plane electromagnetic wave is $2.2 \times 10^{-4} \ T$,then the intensity of the wave is nearly

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