If statements p and q are true and r and s ar | vedclass

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(B) Given: $p = T, q = T, r = F, s = F$. For the first expression $\sim(p \rightarrow q) \leftrightarrow (p \wedge s)$: $\sim(T \rightarrow T) \leftri

Vedclass · Accepted Answer

$T, T$

Vedclass · Answer

(B) Given: $p = T, q = T, r = F, s = F$. For the first expression $\sim(p \rightarrow q) \leftrightarrow (p \wedge s)$: $\sim(T \rightarrow T) \leftrightarrow (T \wedge F)$ $= \sim(T) \leftrightarrow (F)$ $= F \leftrightarrow F = T$. For the second expression $(\sim p \rightarrow q) \wedge (r \leftrightarrow s)$: $(\sim T \rightarrow T) \wedge (F \leftrightarrow F)$ $= (F \rightarrow T) \wedge (T)$ $= T \wedge T = T$. Thus,the truth values are $T, T$.

If statements $p$ and $q$ are true and $r$ and $s$ are false,then the truth values of $\sim(p \rightarrow q) \leftrightarrow (p \wedge s)$ and $(\sim p \rightarrow q) \wedge (r \leftrightarrow s)$ are respectively:

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