If the radius of a sphere is $(5.3 \pm 0.1) \; cm$,then the percentage error in its volume will be:

$A$ physical quantity $X$ is given by $X = \frac{2k^3l^2}{m\sqrt{n}}$. The percentage errors in the measurements of $k, l, m$ and $n$ are $1\%, 2\%, 3\%$ and $4\%$ respectively. The value of $X$ is uncertain by .......... $\%$

The length,breadth,and thickness of a strip are $(10.0 \pm 0.1) \; cm$,$(1.00 \pm 0.01) \; cm$,and $(0.100 \pm 0.001) \; cm$ respectively. The most probable error in its volume will be?

$A$ physical quantity $A$ is related to four observables $a, b, c,$ and $d$ as follows: $A = \frac{a^2 b^3}{c \sqrt{d}}$. The percentage errors of measurement in $a, b, c,$ and $d$ are $1\%, 3\%, 2\%,$ and $2\%$ respectively. What is the percentage error in the quantity $A$?

The formula for the physical quantity is $P = \frac{x^3 y}{z^2}$ and the percentage error in the determination of physical quantities $x, y, z$ are $0.6 \%$,$3 \%$,and $1.3 \%$ respectively. The percentage error in the measurement of $P$ is (in $\%$)

The measurements of two quantities along with the precision of their respective measuring instruments are $A = 2.5 \, m/s \pm 0.5 \, m/s$ and $B = 0.10 \, s \pm 0.01 \, s$. The value of $AB$ will be: