If radius of the earth contracts $2\%$ and its mass remains the same, then weight of the body at the earth surface

At a given place where acceleration due to gravity is $‘g’$ $m/{\sec ^2}$, a sphere of lead of density $‘d’$ $kg/{m^3}$ is gently released in a column of liquid of density $'\rho '\;kg/{m^3}$. If $d > \rho $, the sphere will

If the change in the value of $‘g’$ at a height $h$ above the surface of the earth is the same as at a depth $x$ below it, then (both $x$ and $h$ being much smaller than the radius of the earth)

Mass of moon is $7.34 \times {10^{22}}\,kg$. If the acceleration due to gravity on the moon is $1.4\,m/{s^2}$, the radius of the moon is $(G = 6.667 \times {10^{ - 11}}\,N{m^2}/k{g^2})$

Two masses $m_1$ and $m_2\, (m_1 < m_2)$ are released from rest from a finite distance. They start under their mutual gravitational attraction

Assuming the earth to be a sphere of uniform density, the acceleration due to gravity inside the earth at a distance of $r$ from the centre is proportional to