If one of the roots of the quadratic equation | vedclass

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Question

(B) Let the quadratic equation be $x^{2}+bx-15=0$.Given that one root is $\alpha = 3$.Let the other root be $\beta$.For a quadratic equation $ax^{2}+b

Vedclass · Accepted Answer

$-5$

Vedclass · Answer

(B) Let the quadratic equation be $x^{2}+bx-15=0$.Given that one root is $\alpha = 3$.Let the other root be $\beta$.For a quadratic equation $ax^{2}+bx+c=0$,the product of the roots is given by $\alpha \cdot \beta = \frac{c}{a}$.Here,$a = 1$,$b = b$,and $c = -15$.Substituting the values,we get $3 \cdot \beta = \frac{-15}{1}$.$3 \cdot \beta = -15$.$\beta = \frac{-15}{3} = -5$.Therefore,the other root is $-5$.

If one of the roots of the quadratic equation $x^{2}+bx-15=0$ is $3$,then the other root is ..... .

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